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7x^2+49x=10
We move all terms to the left:
7x^2+49x-(10)=0
a = 7; b = 49; c = -10;
Δ = b2-4ac
Δ = 492-4·7·(-10)
Δ = 2681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{2681}}{2*7}=\frac{-49-\sqrt{2681}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{2681}}{2*7}=\frac{-49+\sqrt{2681}}{14} $
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